(2x-3)^2-(4x)^2/2x=8x/4=-9

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Solution for (2x-3)^2-(4x)^2/2x=8x/4=-9 equation: 



(2x-3)^2-(4x)^2/2x=8x/4=-9

We move all terms to the left:

(2x-3)^2-(4x)^2/2x-(8x/4)=0



Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R



determiningTheFunctionDomain
-4x^2/2x+(2x-3)^2-(8x/4)=0

We add all the numbers together, and all the variables

-4x^2/2x+(2x-3)^2-(+8x/4)=0

We get rid of parentheses

-4x^2/2x+(2x-3)^2-8x/4=0

We calculate fractions


(-16x^2)/8x+(-16x^2)/8x+(2x-3)^2=0

We multiply all the terms by the denominator


(-16x^2)+(-16x^2)+((2x-3)^2)*8x=0

We get rid of parentheses

-16x^2-16x^2+((2x-3)^2)*8x=0

We add all the numbers together, and all the variables

-32x^2+((2x-3)^2)*8x=0

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